regexp in the shell
Dpk
dpk@egr.msu.edu
Thu, 19 Apr 2001 13:12:44 -0400
On Thu, Apr 19, 2001 at 01:10:34PM -0400, Dpk wrote:
On Thu, Apr 19, 2001 at 12:53:50PM -0400, Morris, Alex wrote:
I'm using the ksh shell and have a problem. I have a variable
in one of my scripts, and I need to extract a few characters
from the variable and store it in another variable (preferably
without using a temp file).
The basic format of the variable is:
IMPLEMNTATION ----------------------- xxxxxxxx!yyyyy 1
record(s) selected.
I'm trying to extract that "xxxxxxxx" part. The number of
dashes, "-", is not static. The number of "x"'s is not static.
And the number of "y"'s is not static. I figure that I can
search through the variable and pull out everything between
"----- " and "!", but I don't know how to search through the
variable...
Any idea how to do this, or what function to investigate? I was
looking at grep because it does regexp (which would make this
easy) but it returns lines that match a pattern, it cannot
extract text from a line.
Any ideas?
echo $myvariable |awk '{print $3}' |cut -d\! -f1
Further info, to assign it to a new variable name, just in case there
is confusion:
newvar=`echo $myvariable |awk '{print $3}' |cut -d\! -f1`