[GLLUG] grep help

[Mike Szumlinski]

Okay, I'm trying to parse a large amount of report files for some 
people here at work and I'm pretty sure grep is the tool I need.  The 
one thing I don't know how to do is throw away some of the information 
I'm getting.

Right now, my expression is as follows:

---

myhost:~/Desktop] szumlins% grep "Current\ Machine\|Total\ 
Files\|bytes" sometextfile.txt
Current Machine: whoeverthemachinebelongsto
                1 File(s)      3,492,199 bytes
                2 File(s)      1,374,386 bytes
               14 File(s)     60,253,470 bytes
               12 File(s)     66,581,162 bytes
               16 File(s)     42,781,520 bytes
               16 File(s)     60,159,760 bytes
                5 File(s)     17,112,793 bytes
               12 File(s)     54,080,486 bytes
               17 File(s)     67,632,351 bytes
                1 File(s)      2,624,518 bytes
      Total Files Listed:
               96 File(s)    376,092,645 bytes
                0 Dir(s)  30,038,294,528 bytes free

---

All of the text files have "Current Machine:" in the first line.  All 
of the text files also have "Total Files Listed:" and then the 
information as the last 3 lines.  I only want that information, not all 
the individual files above.  Any quick ideas how I can slap that 
request back into a regexp and eliminate the multiple lines so that my 
output looks like this:

---

Current Machine: whoeverthemachinebelongsto

      Total Files Listed:
               96 File(s)    376,092,645 bytes
                0 Dir(s)  30,038,294,528 bytes free

---

I'm sure this is a quickie for some of you guys, I really appreciate 
the help.

-Mike